To find the displacement s2, we can use the formula:

s2 = s1 + (v^2 - V^2)/2a

where:

s1 = initial displacement = 0.2 m^2V = initial velocity = 3 m/sv = final velocity = 1.2 m/s

Given that the acceleration (a) is not provided, we can use the formula v^2 = u^2 + 2as to solve for acceleration and then find s2 using the formula above.

First, let's solve for acceleration using the above formula:
v^2 = u^2 + 2as
(1.2)^2 = (3)^2 + 2a(0.2)
1.44 = 9 + 0.4a
0.4a = -7.56
a = -18.9 m/s^2

Now, we can find s2:

s2 = 0.2 + (1.2^2 - 3^2)/(2*-18.9)
s2 = 0.2 + (1.44 - 9) / -37.8
s2 = 0.2 + (-7.56) / -37.8
s2 = 0.2 + 0.2
s2 = 0.4 m^2

Therefore, the displacement s2 is 0.4 square meters.