Molecular equation of the reaction: CO2 + H2O = H2CO3

To find the mass of carbonic acid formed, we first need to calculate the moles of CO2 and H2O involved in the reaction.

Calculate the moles of CO2:
24 L of CO2 at STP (standard temperature and pressure) is equal to 1 mole.
So, 24 L of CO2 is equal to 1 mole.

Calculate the moles of H2O:
Using the molar mass of water (H2O):
Molar mass of H2O = 18 g/mol
150 g of H2O is equal to:
150 g / 18 g/mol = 8.33 mol

Now, since the reaction ratio between CO2 and H2O is 1:1, the moles of CO2 and H2O are equal.

Calculate the molar mass of H2CO3 (carbonic acid):
Molar mass of H2CO3 = 62 g/mol

Calculate the mass of carbonic acid formed:
Number of moles of H2CO3 = 8.33 mol
Mass of carbonic acid = number of moles × molar mass
Mass of carbonic acid = 8.33 mol × 62 g/mol = 516.46 g

Therefore, the mass of carbonic acid formed when 24 L of carbon dioxide is passed through 150 g of water is 516.46 g.