To solve the equation Cos(3x-π/6) = Cos(x+π/4), we can use the trigonometric identity: Cos(a) = Cos(b) if and only if a = b + 2πn or a = -b + 2πn, where n is an integer.
So, we need to set up two equations:
3x - π/6 = x + π/43x - π/6 = -(x + π/4)
For equation 1: 3x - x = π/4 + π/6 2x = 5π/12 x = 5π/24
For equation 2: 3x + x = -π/4 + π/6 4x = -π/12 x = -π/48
Therefore, the solutions to the equation Cos(3x-π/6) = Cos(x+π/4) are x = 5π/24 and x = -π/48.
To solve the equation Cos(3x-π/6) = Cos(x+π/4), we can use the trigonometric identity:
Cos(a) = Cos(b) if and only if a = b + 2πn or a = -b + 2πn, where n is an integer.
So, we need to set up two equations:
3x - π/6 = x + π/43x - π/6 = -(x + π/4)For equation 1:
3x - x = π/4 + π/6
2x = 5π/12
x = 5π/24
For equation 2:
3x + x = -π/4 + π/6
4x = -π/12
x = -π/48
Therefore, the solutions to the equation Cos(3x-π/6) = Cos(x+π/4) are x = 5π/24 and x = -π/48.