-x=-2x=2
Plugging in x=2 to the first and second equations:
3(2) - 3y + 3z = 126 - 3y + 3z = 12-3y + 3z = 6-3y = -3z + 6y = z - 2
-2(2) + 3y - 5z = -10-4 + 3y - 5z = -103y - 5z = -63(z - 2) - 5z = -63z - 6 - 5z = -6-2z = 0z = 0
Therefore, x=2, y=-2, z=0
Solution: x=2, y=-2, z=0
-x=-2
x=2
Plugging in x=2 to the first and second equations:
3(2) - 3y + 3z = 12
6 - 3y + 3z = 12
-3y + 3z = 6
-3y = -3z + 6
y = z - 2
-2(2) + 3y - 5z = -10
-4 + 3y - 5z = -10
3y - 5z = -6
3(z - 2) - 5z = -6
3z - 6 - 5z = -6
-2z = 0
z = 0
Therefore, x=2, y=-2, z=0
Solution: x=2, y=-2, z=0