Since a + b = 3, we can rewrite the equation as follows:
a^3 + 3ab(a + b) + b^3 = 9
Now we can substitute a + b = 3 into the equation:
a^3 + 3ab(3) + b^3 = 9a^3 + 9ab + b^3 = 9
Given that a^3 + b^3 = 9, we can substitute this into the equation above:
9 + 9ab = 99ab = 0ab = 0
Therefore, the value of ab is 0.
Since a + b = 3, we can rewrite the equation as follows:
a^3 + 3ab(a + b) + b^3 = 9
Now we can substitute a + b = 3 into the equation:
a^3 + 3ab(3) + b^3 = 9
a^3 + 9ab + b^3 = 9
Given that a^3 + b^3 = 9, we can substitute this into the equation above:
9 + 9ab = 9
9ab = 0
ab = 0
Therefore, the value of ab is 0.