√2x + 3 = x
First, let's isolate the radical on one side:
√2x = x - 3
Next, square both sides of the equation to eliminate the radical:
(√2x)² = (x - 3)²2x = x² - 6x + 9
Now, move all terms to one side of the equation:
0 = x² - 8x + 9
This is a quadratic equation, so let's solve it by factoring:
0 = (x - 1)(x - 9)
Setting each factor to zero:
x - 1 = 0 or x - 9 = 0x = 1 or x = 9
Therefore, the solutions to the equation are x = 1 and x = 9.
√2x + 3 = x
First, let's isolate the radical on one side:
√2x = x - 3
Next, square both sides of the equation to eliminate the radical:
(√2x)² = (x - 3)²
2x = x² - 6x + 9
Now, move all terms to one side of the equation:
0 = x² - 8x + 9
This is a quadratic equation, so let's solve it by factoring:
0 = (x - 1)(x - 9)
Setting each factor to zero:
x - 1 = 0 or x - 9 = 0
x = 1 or x = 9
Therefore, the solutions to the equation are x = 1 and x = 9.