To find the value of the constant c we can plug in y=3 and y'=1 when x=0 into the given differential equation.
y'' + y' - 6y = 0
Substitute y=3, y'=1, x=0 into the equation:
3 + 1 - 6(3) = 04 - 18 = 0-14 = 0
This equation does not hold, there may be an error in either the question or the calculations.
To find the value of the constant c we can plug in y=3 and y'=1 when x=0 into the given differential equation.
y'' + y' - 6y = 0
Substitute y=3, y'=1, x=0 into the equation:
3 + 1 - 6(3) = 0
4 - 18 = 0
-14 = 0
This equation does not hold, there may be an error in either the question or the calculations.