To solve this equation, we will first eliminate the logarithm by raising both sides of the equation as a power of 10. This will allow us to cancel out the logarithm function.
So we have:
2x^2 + 3x = 6x + 2
Now let's simplify this equation by moving all terms to one side:
2x^2 + 3x - 6x - 2 = 0
Rearranging the terms:
2x^2 - 3x - 2 = 0
Now we have a quadratic equation. Let's solve it by factoring or using the quadratic formula:
We can factor this equation as:
(2x + 1)(x - 2) = 0
This gives us two possible solutions:
2x + 1 = 0 x = -1/2
x - 2 = 0 x = 2
So the two solutions for the given equation are x = -1/2 and x = 2.
To solve this equation, we will first eliminate the logarithm by raising both sides of the equation as a power of 10. This will allow us to cancel out the logarithm function.
So we have:
2x^2 + 3x = 6x + 2
Now let's simplify this equation by moving all terms to one side:
2x^2 + 3x - 6x - 2 = 0
Rearranging the terms:
2x^2 - 3x - 2 = 0
Now we have a quadratic equation. Let's solve it by factoring or using the quadratic formula:
We can factor this equation as:
(2x + 1)(x - 2) = 0
This gives us two possible solutions:
2x + 1 = 0
x = -1/2
x - 2 = 0
x = 2
So the two solutions for the given equation are x = -1/2 and x = 2.