To solve the equation Sin(2x) + √3sin(x) = 0, we can rewrite it in terms of sin(2x) using the double angle identity:

Sin(2x) + √3sin(x) = 0
2sin(x)cos(x) + √3sin(x) = 0
sin(x)(2cos(x) + √3) = 0

Now we have two possibilities:

1) sin(x) = 0
This occurs when x is a multiple of π (pi), so x = nπ where n is an integer.

2) 2cos(x) + √3 = 0
cos(x) = -√3/2
This occurs when x = 5π/6 + 2nπ or x = 7π/6 + 2nπ, where n is an integer.

Therefore, the solutions to the equation Sin(2x) + √3sin(x) = 0 are x = nπ, x = 5π/6 + 2nπ, or x = 7π/6 + 2nπ, where n is an integer.