To simplify this expression, we can use the property of logarithms that states log(base a)(b) + log(base a)(c) = log(base a)(b * c).
Therefore, log35(1/5) + log35(1/7) = log35((1/5) * (1/7)) = log35(1/35) = -1.
So, log35(1/5) + log35(1/7) simplifies to -1.
To simplify this expression, we can use the property of logarithms that states log(base a)(b) + log(base a)(c) = log(base a)(b * c).
Therefore, log35(1/5) + log35(1/7) = log35((1/5) * (1/7)) = log35(1/35) = -1.
So, log35(1/5) + log35(1/7) simplifies to -1.