(36 · sin13 · cos13) ÷ sin26
Firstly, we can simplify the expression by noting that sin(2θ) = 2sinθcosθ.
Therefore, sin(26) = 2sin13cos13. So, the expression becomes:
(36 · sin13 · cos13) ÷ (2sin13cos13)
Now we can cancel out sin13cos13 from the numerator and denominator, getting:
36 ÷ 2 = 18
So, the simplified expression is 18.
(36 · sin13 · cos13) ÷ sin26
Firstly, we can simplify the expression by noting that sin(2θ) = 2sinθcosθ.
Therefore, sin(26) = 2sin13cos13. So, the expression becomes:
(36 · sin13 · cos13) ÷ (2sin13cos13)
Now we can cancel out sin13cos13 from the numerator and denominator, getting:
36 ÷ 2 = 18
So, the simplified expression is 18.