To find the lengths of BC and AC, we will use the sine and cosine trigonometric ratios.
Given:Angle C = 90°Angle A = 60°Side AB = 5√3
First, let's find the length of side BC oppositeangleAopposite angle AoppositeangleA:
sin60°60°60° = BC / ABsin60°60°60° = BC / 5√3BC = 5√3 sin60°60°60° BC ≈ 5 0.866BC ≈ 4.33
Next, let's find the length of side AC oppositerightangleCopposite right angle CoppositerightangleC:
cos60°60°60° = AC / ABcos60°60°60° = AC / 5√3AC = 5√3 cos60°60°60° AC ≈ 5 0.5AC ≈ 2.50
Therefore, the length of side BC is approximately 4.33 and the length of side AC is approximately 2.50.
To find the lengths of BC and AC, we will use the sine and cosine trigonometric ratios.
Given:
Angle C = 90°
Angle A = 60°
Side AB = 5√3
First, let's find the length of side BC oppositeangleAopposite angle AoppositeangleA:
sin60°60°60° = BC / AB
sin60°60°60° = BC / 5√3
BC = 5√3 sin60°60°60° BC ≈ 5 0.866
BC ≈ 4.33
Next, let's find the length of side AC oppositerightangleCopposite right angle CoppositerightangleC:
cos60°60°60° = AC / AB
cos60°60°60° = AC / 5√3
AC = 5√3 cos60°60°60° AC ≈ 5 0.5
AC ≈ 2.50
Therefore, the length of side BC is approximately 4.33 and the length of side AC is approximately 2.50.