Molar mass of Na2S: M(Na2S) = 22.99*2 + 32.06 = 78.04 g/mol
Now we can calculate the number of moles of Na2S:
n(Na2S) = m(S) / M(Na2S)n(Na2S) = 12.8 / 78.04n(Na2S) ≈ 0.164 mol
Therefore, the number of moles of Na2S in 12.8 g of sulfur is approximately 0.164 mol.
Molar mass of Na2S: M(Na2S) = 22.99*2 + 32.06 = 78.04 g/mol
Now we can calculate the number of moles of Na2S:
n(Na2S) = m(S) / M(Na2S)
n(Na2S) = 12.8 / 78.04
n(Na2S) ≈ 0.164 mol
Therefore, the number of moles of Na2S in 12.8 g of sulfur is approximately 0.164 mol.