To find the amount of Kp given the amounts of Mb and N2O, we first need to determine the molar mass of each compound.

Molar mass of Mb (methylene blue):
C16H18ClN3S = 16(12.01) + 18(1.008) + 1(35.45) + 3(14.01) + 1(32.06) = 319.87 g/mol

Molar mass of N2O (nitrous oxide):
28.02 + 2(16.00) = 44.02 g/mol

Next, we convert the given masses to moles:

moles of Mb = 40 g / 319.87 g/mol ≈ 0.125 moles
moles of N2O = 160 g / 44.02 g/mol ≈ 3.63 moles

The balanced chemical equation for the reaction between Mb and N2O is:

2 Mb + 4 N2O → 2 Kp

From the balanced equation, the mole ratio between Mb and Kp is 2:2, which simplifies to 1:1. Therefore, the moles of Kp formed will be equal to the moles of Mb consumed.

moles of Kp formed = 0.125 moles

Finally, we calculate the mass of Kp formed:

mass of Kp = moles of Kp formed x molar mass of Kp
mass of Kp = 0.125 moles x 144 g/mol ≈ 18 g

Therefore, approximately 18 grams of Kp will be formed.