To solve the inequality log1/2(3x + 1) ≤ 16, we first need to rewrite it in exponential form.
The base of the logarithm is 1/2, so we have:
1/2^16 ≤ 3x + 1
Now we can solve for x:
1/65536 ≤ 3x
1/65536 / 3 ≤ x
1/196608 ≤ x
Therefore, the solution to the inequality log1/2(3x + 1) ≤ 16 is x ≥ 1/196608.
To solve the inequality log1/2(3x + 1) ≤ 16, we first need to rewrite it in exponential form.
The base of the logarithm is 1/2, so we have:
1/2^16 ≤ 3x + 1
Now we can solve for x:
1/65536 ≤ 3x
1/65536 / 3 ≤ x
1/196608 ≤ x
Therefore, the solution to the inequality log1/2(3x + 1) ≤ 16 is x ≥ 1/196608.