To solve the logarithmic equation log₄(4x-3) = 2, we first need to rewrite it in exponential form.
According to the definition of logarithms, logₐ(b) = c is equivalent to a^c = b.
So, log₄(4x-3) = 2 can be rewritten as 4^2 = 4x-3.
Simplifying, we get 16 = 4x-3.
Add 3 to both sides: 16 + 3 = 4x
19 = 4x
Divide by 4: 19/4 = x
Therefore, x = 4.75.
To solve the logarithmic equation log₄(4x-3) = 2, we first need to rewrite it in exponential form.
According to the definition of logarithms, logₐ(b) = c is equivalent to a^c = b.
So, log₄(4x-3) = 2 can be rewritten as 4^2 = 4x-3.
Simplifying, we get 16 = 4x-3.
Add 3 to both sides: 16 + 3 = 4x
19 = 4x
Divide by 4: 19/4 = x
Therefore, x = 4.75.