To solve this equation, we first need to isolate the square root term on one side of the equation:

From Log2 (√x-2) = 1
We can rewrite it as 2^1 = √x-2
Which simplifies to 2 = √x - 2

Next, we isolate the square root term:
Add 2 to both sides: 2 + 2 = √x
4 = √x

Now square both sides to get rid of the square root:
(4)^2 = (√x)^2
16 = x

Therefore, the solution to the equation Log2 (√x-2) = 1 is x = 16.