To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method.
From the first equation, we can solve for y in terms of x:
4x + y = 3y = 3 - 4x
Now, substitute this expression for y into the second equation:
6x - 2(3 - 4x) = 16x - 6 + 8x = 114x - 6 = 114x = 7x = 7/14x = 1/2
Now that we have found the value of x, we can substitute it back into the first equation to find y:
4(1/2) + y = 32 + y = 3y = 1
Therefore, the solution to the system of equations is x = 1/2 and y = 1.
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method.
From the first equation, we can solve for y in terms of x:
4x + y = 3
y = 3 - 4x
Now, substitute this expression for y into the second equation:
6x - 2(3 - 4x) = 1
6x - 6 + 8x = 1
14x - 6 = 1
14x = 7
x = 7/14
x = 1/2
Now that we have found the value of x, we can substitute it back into the first equation to find y:
4(1/2) + y = 3
2 + y = 3
y = 1
Therefore, the solution to the system of equations is x = 1/2 and y = 1.