To solve this equation, we can rewrite it as:
1 + (sin^2x + cos^2x) + cosx = 0
Since sin^2x + cos^2x = 1, we have:
1 + 1 + cosx = 0
2 + cosx = 0
cosx = -2
However, the cosine function is always between -1 and 1, so there is no solution to this equation.
To solve this equation, we can rewrite it as:
1 + (sin^2x + cos^2x) + cosx = 0
Since sin^2x + cos^2x = 1, we have:
1 + 1 + cosx = 0
2 + cosx = 0
cosx = -2
However, the cosine function is always between -1 and 1, so there is no solution to this equation.