2а-(3b-a)+(3b-2a) = 2a - 3b + a + 3b - 2a= 2a - 3b + a + 3b - 2a= 3a
6(a-2)-3(2a-5) = 6a - 12 - 6a + 15= 3
(x+3)(2-x) = 0Expanding the expression:= 2x - x + 6 - 3= x + 3
Therefore, the solutions are 3a, 3, and x + 3 = 0.
2а-(3b-a)+(3b-2a) = 2a - 3b + a + 3b - 2a
= 2a - 3b + a + 3b - 2a
= 3a
6(a-2)-3(2a-5) = 6a - 12 - 6a + 15
= 3
(x+3)(2-x) = 0
Expanding the expression:
= 2x - x + 6 - 3
= x + 3
Therefore, the solutions are 3a, 3, and x + 3 = 0.