(p+3)(p-1) + (p+6)^2
Expanding the first term:= p^2 - p + 3p - 3
Expanding the second term:= p^2 + 12p + 36
Adding both terms together:= p^2 - p + 3p - 3 + p^2 + 12p + 36= 2p^2 + 14p + 33
Therefore, (p+3)(p-1) + (p+6)^2 is equal to 2p^2 + 14p + 33.
(p+3)(p-1) + (p+6)^2
Expanding the first term:
= p^2 - p + 3p - 3
Expanding the second term:
= p^2 + 12p + 36
Adding both terms together:
= p^2 - p + 3p - 3 + p^2 + 12p + 36
= 2p^2 + 14p + 33
Therefore, (p+3)(p-1) + (p+6)^2 is equal to 2p^2 + 14p + 33.