To solve this equation, we can first rewrite it in terms of sine and cosine:

$2sin(t)-3cos(t)$ / $2cos(t)-3sin(t)$ = 3

Next, we can multiply both sides by $2cos(t)-3sin(t)$ to get rid of the denominator:

2sin$t$ - 3cos$t$ = 3$2cos(t)-3sin(t)$

Expanding both sides, we get:

2sin$t$ - 3cos$t$ = 6cos$t$ - 9sin$t$

Rearranging terms, we get:

2sin$t$ + 9sin$t$ = 6cos$t$ + 3cos$t$

11sin$t$ = 9cos$t$

Now we can divide both sides by 11sin$t$ to isolate cos$t$:

cos$t$ = 9/11sin$t$

Finally, we can use the Pythagorean identity sin^2$t$ + cos^2$t$ = 1 to solve for sin$t$ and cos$t$ simultaneously.