(y-3)(5+2y)-(5-2y)^2=0
Expanding the terms:
5y + 2y^2 - 15 - 6y - (25 - 20y + 4y^2) = 0
Combine like terms:
2y^2 + 5y - 15 - 6y - 25 + 20y - 4y^2 = 0
-2y^2 + 19y - 40 = 0
Rearrange the terms:
2y^2 - 19y + 40 = 0
Factor the quadratic equation:
(2y - 5)(y - 8) = 0
y = 5/2 or y = 8

Therefore, the solutions to the equation are y = 5/2 or y = 8.