To solve the quadratic equation:
x^2 + 3x + 4 = 0
We can use the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
In this case, a = 1, b = 3, and c = 4. Plugging these values into the quadratic formula:
x = [-3 ± √(3^2 - 414)] / 2*1
x = [-3 ± √(9 - 16)] / 2
x = [-3 ± √(-7)] / 2
Since the square root of a negative number is not a real number, the solutions to this quadratic equation are complex numbers.
To solve the quadratic equation:
x^2 + 3x + 4 = 0
We can use the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
In this case, a = 1, b = 3, and c = 4. Plugging these values into the quadratic formula:
x = [-3 ± √(3^2 - 414)] / 2*1
x = [-3 ± √(9 - 16)] / 2
x = [-3 ± √(-7)] / 2
Since the square root of a negative number is not a real number, the solutions to this quadratic equation are complex numbers.