To solve this equation, we need to cross multiply:
(x + 1)(3x + 1) = (2x - 1)(x - 1)
Expanding both sides:
3x^2 + x + 3x + 1 = 2x^2 - 2x - x + 1
Combining like terms:
3x^2 + 4x + 1 = 2x^2 - 3x + 1
Subtracting (2x^2 - 3x + 1) from both sides:
3x^2 + 4x + 1 - 2x^2 + 3x - 1 = 0
x^2 + 7x = 0
This simplifies to:
x(x + 7) = 0
Therefore, the solutions for x are:
x = 0 or x = -7
To solve this equation, we need to cross multiply:
(x + 1)(3x + 1) = (2x - 1)(x - 1)
Expanding both sides:
3x^2 + x + 3x + 1 = 2x^2 - 2x - x + 1
Combining like terms:
3x^2 + 4x + 1 = 2x^2 - 3x + 1
Subtracting (2x^2 - 3x + 1) from both sides:
3x^2 + 4x + 1 - 2x^2 + 3x - 1 = 0
x^2 + 7x = 0
This simplifies to:
x(x + 7) = 0
Therefore, the solutions for x are:
x = 0 or x = -7