To solve the equation Log5 (√x-3) = 1, we need to rewrite it in exponential form.

Using the definition of logarithms, we know that Loga(b) = c is equivalent to a^c = b.

So, for our equation Log5 (√x-3) = 1, we have:

5^1 = √x - 3

Simplifying further, we get:

5 = √x - 3

Adding 3 to both sides gives us:

8 = √x

Now, square both sides to get rid of the square root:

8^2 = x

64 = x

Therefore, the solution to the equation Log5 (√x-3) = 1 is x = 64.