To solve the equation |3x+1|+2²=8, we first need to consider two cases:
Case 1: 3x+1 is positive or zero3x+1+4=83x+5=83x=3x=1
Case 2: 3x+1 is negative-(3x+1)+4=8-3x-1+4=8-3x+3=8-3x=5x=-5/3
Therefore, the solutions to |3x+1|+2²=8 are x=1 and x=-5/3.
To solve the equation |9x+2|-3³=(-3)³, we first simplify the absolute value:
|9x+2|-27=-27
|9x+2|=0
9x+2=0
9x=-2
x=-2/9
Therefore, the solution to |9x+2|-3³=(-3)³ is x=-2/9.
To solve the equation |3x+1|+2²=8, we first need to consider two cases:
Case 1: 3x+1 is positive or zero
3x+1+4=8
3x+5=8
3x=3
x=1
Case 2: 3x+1 is negative
-(3x+1)+4=8
-3x-1+4=8
-3x+3=8
-3x=5
x=-5/3
Therefore, the solutions to |3x+1|+2²=8 are x=1 and x=-5/3.
To solve the equation |9x+2|-3³=(-3)³, we first simplify the absolute value:
|9x+2|-27=-27
|9x+2|=0
9x+2=0
9x=-2
x=-2/9
Therefore, the solution to |9x+2|-3³=(-3)³ is x=-2/9.