To solve this equation, we need to use the property of logarithms that states loga(b) = logc(d) if and only if b = d.
Therefore, we can rewrite the equation as:
7x - 9 = x
Now we can solve for x:
7x - x = 96x = 9x = 9/6x = 3/2
Therefore, the solution to the equation log1/6(7x-9) = log1/6x is x = 3/2.
To solve this equation, we need to use the property of logarithms that states loga(b) = logc(d) if and only if b = d.
Therefore, we can rewrite the equation as:
7x - 9 = x
Now we can solve for x:
7x - x = 9
6x = 9
x = 9/6
x = 3/2
Therefore, the solution to the equation log1/6(7x-9) = log1/6x is x = 3/2.