To calculate the heat transfer when a 2 kg mass is cooled from 100°C to 0°C, we will use the formula:
Q = mcΔT
Where: Q = Heat transfer m = Mass (2 kg) c = Specific heat capacity of water (assuming it's water) = 4.184 J/g°C ΔT = Change in temperature = t2 - t1 = 0°C - 100°C = -100°C
Now we convert the mass from kg to grams: m = 2 kg = 2000 g
Plug in the values: Q = 2000 g 4.184 J/g°C (-100°C) Q = -836,800 J
Therefore, the heat transfer when a 2 kg mass is cooled from 100°C to 0°C is -836,800 Joules.
To calculate the heat transfer when a 2 kg mass is cooled from 100°C to 0°C, we will use the formula:
Q = mcΔT
Where:
Q = Heat transfer
m = Mass (2 kg)
c = Specific heat capacity of water (assuming it's water) = 4.184 J/g°C
ΔT = Change in temperature = t2 - t1 = 0°C - 100°C = -100°C
Now we convert the mass from kg to grams:
m = 2 kg = 2000 g
Plug in the values:
Q = 2000 g 4.184 J/g°C (-100°C)
Q = -836,800 J
Therefore, the heat transfer when a 2 kg mass is cooled from 100°C to 0°C is -836,800 Joules.