To find tg α tangentofαtangent of αtangentofα, we use the formula:
tg α = sin α / cos α
Given that cos α = 8/17, we first need to find sin α before we can find tg α.
Since sin^2 α + cos^2 α = 1, we can find sin α:
sin^2 α + 8/178/178/17^2 = 1sin^2 α + 64/289 = 1sin^2 α = 1 - 64/289sin^2 α = 225/289sin α = √225/289225/289225/289 sin α = 15/17
Now that we have sin α, we can find tg α:
tg α = sin α / cos αtg α = 15/1715/1715/17 / 8/178/178/17 tg α = 15/8
Therefore, tg α = 15/8.
To find tg α tangentofαtangent of αtangentofα, we use the formula:
tg α = sin α / cos α
Given that cos α = 8/17, we first need to find sin α before we can find tg α.
Since sin^2 α + cos^2 α = 1, we can find sin α:
sin^2 α + 8/178/178/17^2 = 1
sin^2 α + 64/289 = 1
sin^2 α = 1 - 64/289
sin^2 α = 225/289
sin α = √225/289225/289225/289 sin α = 15/17
Now that we have sin α, we can find tg α:
tg α = sin α / cos α
tg α = 15/1715/1715/17 / 8/178/178/17 tg α = 15/8
Therefore, tg α = 15/8.