19 Фев 2020 в 19:52
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The given reaction is the conversion of ethyl bromide C2H5BrC2H5BrC2H5Br to butane C4H10C4H10C4H10 through a substitution reaction.

C2H5Br -> C4H10

This reaction can occur through a series of steps, where the ethyl bromide undergoes nucleophilic substitution to form butane.

C2H5Br + NaOH -> C2H5OH + NaBr EliminationreactiontoformethanolElimination reaction to form ethanolEliminationreactiontoformethanol C2H5OH -> C4H10 + CH3OOH DehydrationreactiontoformbutaneandaceticacidDehydration reaction to form butane and acetic acidDehydrationreactiontoformbutaneandaceticacid

Therefore, the final products of the reaction of ethyl bromide with NaOH followed by dehydration are butane C4H10C4H10C4H10 and acetic acid CH3OOHCH3OOHCH3OOH.

18 Апр 2024 в 17:00
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