а) log3$x+1$ = 0
x + 1 = 3^0
x + 1 = 1
x = 0

б) log2$x-5$ + log2$x+2$ = log2$18$ log2$(x-5)(x+2)$ = log2$18$ $x-5$$x+2$ = 18
x^2 - 3x - 10 = 18
x^2 - 3x - 28 = 0
$x-7$$x+4$ = 0
x = 7, x = -4

в) log3^x - log3x = 2
log3^x / 3 = 3
3^$log{3}^x$ = 3^3
x = 3^3
x = 27