This sequence has 4n numbers arranged in a special way:

1, 5, ..., 4n-3, 2, 6, ..., 4n-2, 3, 7, ..., 4n-1, 4, 8, ..., 4n

To find the number of inversions, we need to count the number of pairs of elements that are in the wrong order. In this sequence, each element is exactly (4n-1) positions away from its correct position. Therefore, the total number of inversions is (4n-1)*(4n)/2 = 2n(4n-1).

To determine the uniformity of the displacement, we can observe that each element is shifted by a constant amount of 4. Therefore, the displacement is uniform in this sequence.

In conclusion, the number of inversions in this sequence is 2n(4n-1) and the displacement is uniform.