To find the solutions for this equation, we can set each factor equal to zero:
2cosx + 1 = 0cosx = -1/2x = 2π/3, 4π/3
√sinx−1sinx-1sinx−1 = 0√sinxsinxsinx = 1sinx = 1x = π/2
Therefore, the solutions to the equation are x = π/2, 2π/3, 4π/3.
To find the solutions for this equation, we can set each factor equal to zero:
2cosx + 1 = 0
cosx = -1/2
x = 2π/3, 4π/3
√sinx−1sinx-1sinx−1 = 0
√sinxsinxsinx = 1
sinx = 1
x = π/2
Therefore, the solutions to the equation are x = π/2, 2π/3, 4π/3.