Now, we want to find the value of х that would make the expression equal to -15:
х⁴ + 16х³ + 86х² + 176х + 105 = -15
Rearranging the terms, we get:
х⁴ + 16х³ + 86х² + 176х + 120 = 0
Unfortunately, this is a quartic equation and solving it would involve more complex methods than simple algebra. However, we can find approximate solutions using numerical methods or a graphing calculator.
First, let's multiply out the two polynomials:
х2+8х+7х² + 8х + 7х2+8х+7х2+8х+15х² + 8х + 15х2+8х+15 = х⁴ + 8х³ + 15х² + 8х³ + 64х² + 120х + 7х² + 56х + 105
= х⁴ + 16х³ + 86х² + 176х + 105
Now, we want to find the value of х that would make the expression equal to -15:
х⁴ + 16х³ + 86х² + 176х + 105 = -15
Rearranging the terms, we get:
х⁴ + 16х³ + 86х² + 176х + 120 = 0
Unfortunately, this is a quartic equation and solving it would involve more complex methods than simple algebra. However, we can find approximate solutions using numerical methods or a graphing calculator.