Let's simplify the given expression and solve for x.

Let (y = (2x - 1)^2).

Substitute y into the equation given: (y^2 - y - 12 = 0).

Factor the equation: ((y-4)(y+3) = 0).

Since y = (2x - 1)^2, we have two cases to consider:

Case 1: (y - 4 = 0)
(2x - 1 = ±2)
(2x = 1 ± 2)
(x = 3/2, -1/2)

Case 2: (y + 3 = 0)
(2x - 1 = -√3)
(2x = 1 - √3)
(x = (1 - √3)/2)

So the solutions to the equation are (x = 3/2, -1/2, (1-√3)/2).