1) Для функции f(x) = 2x^2 - 25x:
a) Найдем f(-2):f(-2) = 2(-2)^2 - 25(-2) = 2(4) + 50 = 8 + 50 = 58
b) Найдем f(0):f(0) = 2(0)^2 - 25(0) = 0 - 0 = 0
c) Найдем f(6):f(6) = 2(6)^2 - 25(6) = 2(36) - 150 = 72 - 150 = -78
Итак, f(-2) = 58, f(0) = 0, f(6) = -78.
1) Для функции f(x) = 2x^2 - 25x:
a) Найдем f(-2):
f(-2) = 2(-2)^2 - 25(-2) = 2(4) + 50 = 8 + 50 = 58
b) Найдем f(0):
f(0) = 2(0)^2 - 25(0) = 0 - 0 = 0
c) Найдем f(6):
f(6) = 2(6)^2 - 25(6) = 2(36) - 150 = 72 - 150 = -78
Итак, f(-2) = 58, f(0) = 0, f(6) = -78.