To solve this inequality, we first need to find the critical points where the expression is equal to zero.
(-5x - 2) = 0-5x = 2x = -2/5
(2 - 3x) = 0-3x = -2x = 2/3
(-x - 5) = 0-x = 5x = -5
Test interval (-∞, -5):(-)(-)(-) = -Therefore, the expression is negative in this interval.
Test interval (-5, -2/5):(-)(-)(-) = -Therefore, the expression is negative in this interval.
Test interval (-2/5, 2/3):(-)(+)(-) = +Therefore, the expression is positive in this interval.
Test interval (2/3, ∞):(-)(+)(+) = -Therefore, the expression is negative in this interval.
(-x - 5) = 0x = -5
So, the solution to the inequality is x ∈ (-∞, -5] ∪ [-2/5, 2/3].
To solve this inequality, we first need to find the critical points where the expression is equal to zero.
Set each factor equal to zero and solve for x:(-5x - 2) = 0
-5x = 2
x = -2/5
(2 - 3x) = 0
-3x = -2
x = 2/3
(-x - 5) = 0
Now, we determine the sign of each factor in the intervals created by these critical points (-5, -2/5, 2/3, -5).-x = 5
x = -5
Test interval (-∞, -5):
(-)(-)(-) = -
Therefore, the expression is negative in this interval.
Test interval (-5, -2/5):
(-)(-)(-) = -
Therefore, the expression is negative in this interval.
Test interval (-2/5, 2/3):
(-)(+)(-) = +
Therefore, the expression is positive in this interval.
Test interval (2/3, ∞):
Finally, we consider the case where the expression is equal to zero:(-)(+)(+) = -
Therefore, the expression is negative in this interval.
(-x - 5) = 0
x = -5
So, the solution to the inequality is x ∈ (-∞, -5] ∪ [-2/5, 2/3].