First equation:
3(x-5) = x+3Distribute the 3 to both terms inside the parentheses:
3x - 15 = x + 3Combine like terms by subtracting x from both sides:
2x - 15 = 3Add 15 to both sides:
2x = 18Divide by 2:
x = 9
Second equation:
7(x+6) = 4(5x+4)Distribute the 7 and 4 to the terms inside the parentheses:
7x + 42 = 20x + 16Subtract 7x from both sides:
42 = 13x + 16Subtract 16 from both sides:
26 = 13xDivide by 13:
x = 2
Therefore, the solution to the system of equations is x = 9.
First equation:
3(x-5) = x+3
Distribute the 3 to both terms inside the parentheses:
3x - 15 = x + 3
Combine like terms by subtracting x from both sides:
2x - 15 = 3
Add 15 to both sides:
2x = 18
Divide by 2:
x = 9
Second equation:
7(x+6) = 4(5x+4)
Distribute the 7 and 4 to the terms inside the parentheses:
7x + 42 = 20x + 16
Subtract 7x from both sides:
42 = 13x + 16
Subtract 16 from both sides:
26 = 13x
Divide by 13:
x = 2
Therefore, the solution to the system of equations is x = 9.