(х+4)*(х-3) >0
This is a quadratic equation in the form of (x+a)(x+b), where a=4 and b=-3.
To find the values of x that make the expression greater than 0, we need to determine the signs of the factors (x+4) and (x-3) separately.

For (x+4) to be greater than 0, x must be greater than -4.
For (x-3) to be greater than 0, x must be greater than 3.

Therefore, the solution is x > 4.

0.6(2x+5) > 0.6(4x)
Multiply both sides by 10 to eliminate the decimals:
6(2x+5) > 6(4x)
12x + 30 > 24x
Subtract 12x from both sides:
30 > 12x
Divide by 12:
2.5 > x

Therefore, x is greater than 2.5.