(0.3x + 4y)^2 = (0.3x + 4y)(0.3x + 4y)Expanding using the distributive property:= 0.3x 0.3x + 0.3x 4y + 4y 0.3x + 4y 4y= 0.09x^2 + 1.2xy + 1.2xy + 16y^2= 0.09x^2 + 2.4xy + 16y^2
Therefore, (0.3x + 4y)^2 = 0.09x^2 + 2.4xy + 16y^2
(0.3x + 4y)^2 = (0.3x + 4y)(0.3x + 4y)
Expanding using the distributive property:
= 0.3x 0.3x + 0.3x 4y + 4y 0.3x + 4y 4y
= 0.09x^2 + 1.2xy + 1.2xy + 16y^2
= 0.09x^2 + 2.4xy + 16y^2
Therefore, (0.3x + 4y)^2 = 0.09x^2 + 2.4xy + 16y^2