9 Авг 2021 в 19:40
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Ответы
1

To solve this equation, we can start by using the trigonometric identity:

cosxxx * cosyyy = 0.5cos(x+y)+cos(x−y)cos(x+y) + cos(x-y)cos(x+y)+cos(xy)

So the given equation becomes:

0.5cos(10x+7x)+cos(10x−7x)cos(10x+7x) + cos(10x-7x)cos(10x+7x)+cos(10x7x) - 0.5cos(2x+15x)+cos(2x−15x)cos(2x+15x) + cos(2x-15x)cos(2x+15x)+cos(2x15x) = 0

Simplify this to get:

0.5cos(17x)+cos(3x)cos(17x) + cos(3x)cos(17x)+cos(3x) - 0.5cos(17x)+cos(13x)cos(17x) + cos(13x)cos(17x)+cos(13x) = 0

Now combine like terms:

0.5cos(3x)−cos(13x)cos(3x) - cos(13x)cos(3x)cos(13x) = 0

Now, we have that:

cos3x3x3x - cos13x13x13x = 0

Using the trigonometric identity:

cosaaa - cosbbb = -2sin(a+b)/2(a+b)/2(a+b)/2sin(a−b)/2(a-b)/2(ab)/2

We can rewrite the equation as:

-2sin8x8x8xsin5x5x5x = 0

Now, we have two cases to consider:

1) sin8x8x8x = 0
2) sin5x5x5x = 0

For case 1, sin8x8x8x = 0 implies that 8x = nπ, where n is an integer.
So, x = nπ / 8

For case 2, sin5x5x5x = 0 implies that 5x = nπ, where n is an integer.
So, x = nπ / 5

Therefore, the solutions to the given equation are x = nπ / 8 and x = nπ / 5, where n is an integer.

17 Апр 2024 в 13:33
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