sin(3π/4) = -√2/2cos(π/4) = √2/2cos(3π/4) = -√2/2sin(π/4) = √2/2
Теперь вычислим их произведения:
(-√2/2)(√2/2) + (-√2/2)(√2/2) = -2/4 + -2/4 = -1/2 - 1/2 = -1
Ответ: -1
sin(3π/4) = -√2/2
cos(π/4) = √2/2
cos(3π/4) = -√2/2
sin(π/4) = √2/2
Теперь вычислим их произведения:
(-√2/2)(√2/2) + (-√2/2)(√2/2) = -2/4 + -2/4 = -1/2 - 1/2 = -1
Ответ: -1