To solve the equation 2sinx = √3, we need to isolate the sinx term by dividing both sides by 2:
sinx = √3/2
Now, we need to find the angles in the unit circle where sinx = √3/2. The sine function is positive in the first and second quadrants.
In the unit circle, sin30°30°30° = 1/2 and sin60°60°60° = √3/2.
Therefore, the solutions to the equation sinx = √3/2 are x = 60° + 360°n and x = 120° + 360°n, where n is an integer.
To solve the equation 2sinx = √3, we need to isolate the sinx term by dividing both sides by 2:
sinx = √3/2
Now, we need to find the angles in the unit circle where sinx = √3/2. The sine function is positive in the first and second quadrants.
In the unit circle, sin30°30°30° = 1/2 and sin60°60°60° = √3/2.
Therefore, the solutions to the equation sinx = √3/2 are x = 60° + 360°n and x = 120° + 360°n, where n is an integer.