To solve the equation 2sin²x - sinx*cosx - cos²x = 0, we can rewrite it in terms of sinx and cosx:
2(sin²x - cos²x) - sinx*cosx = 0
Using the trigonometric identity sin²x - cos²x = -1, we can simplify the equation further:
2(-1) - sinxcosx = 0-2 - sinxcosx = 0
Now, we can substitute -sinx*cosx with -sin(2x)/2 (by using the double angle identity for sine) to get:
-2 - sin(2x)/2 = 0sin(2x) = -4
However, the sine function only takes values between -1 and 1, so there are no solutions to this equation.
To solve the equation 2sin²x - sinx*cosx - cos²x = 0, we can rewrite it in terms of sinx and cosx:
2(sin²x - cos²x) - sinx*cosx = 0
Using the trigonometric identity sin²x - cos²x = -1, we can simplify the equation further:
2(-1) - sinxcosx = 0
-2 - sinxcosx = 0
Now, we can substitute -sinx*cosx with -sin(2x)/2 (by using the double angle identity for sine) to get:
-2 - sin(2x)/2 = 0
sin(2x) = -4
However, the sine function only takes values between -1 and 1, so there are no solutions to this equation.