(3a^2 + 2b^3)^2 = (3a^2 + 2b^3)(3a^2 + 2b^3)Expanding using the distributive property:= 9a^4 + 6a^2b^3 + 6a^2b^3 + 4b^6= 9a^4 + 12a^2b^3 + 4b^6
Therefore, (3a^2 + 2b^3)^2 = 9a^4 + 12a^2b^3 + 4b^6.
(3a^2 + 2b^3)^2 = (3a^2 + 2b^3)(3a^2 + 2b^3)
Expanding using the distributive property:
= 9a^4 + 6a^2b^3 + 6a^2b^3 + 4b^6
= 9a^4 + 12a^2b^3 + 4b^6
Therefore, (3a^2 + 2b^3)^2 = 9a^4 + 12a^2b^3 + 4b^6.