To solve this inequality, we need to first rewrite it in exponential form:

Next, we need to simplify the inequality:

2^$-1/Log[2,(7-x)]$ > $3-2x$^$-2$ 1/2^$1/Log[2,(7-x)]$ > 1/$3-2x$^2

Now, we can rewrite the inequality in exponential form:

Log$$2,(7-x)$$ < 2
7-x < 2^2
7-x < 4
-x < -3
x > 3

Therefore, the solution to the inequality is x > 3.