To solve this inequality, we first need to rewrite it in a different form.

Using properties of logarithms, we can rewrite the inequality as:
log$$3,((x+1)/(x-1))$$^$1/2$ ≥ 0

Now, we can remove the logarithm by raising 3 to the power of both sides:
$(x+1)/(x-1)$^$1/2$ ≥ 1

Square both sides to simplify:
$x+1$/$x-1$ ≥ 1

Now we can further simplify by multiplying both sides by $x-1$:
x+1 ≥ x-1

Subtract x from both sides:
1 ≥ -1

This inequality is always true, meaning that the original inequality is also true for all real numbers x. Thus, the solution is:
x belongs to R $allrealnumbers$