To find the solutions for each equation:

X(x+3)(x+3)=0
Set each factor to 0:
1) X = 0
2) (x+3) = 0
3) (x+3) = 0

So, the solutions are X = 0, x = -3, x = -3

(x+1)(x-1)(x-5)=0
Set each factor to 0:
1) (x+1) = 0
2) (x-1) = 0
3) (x-5) = 0

So, the solutions are x = -1, x = 1, x = 5

Therefore, the solutions are:
X = 0, x = -3 for the first equation.
x = -1, x = 1, x = 5 for the second equation.