To solve the inequality log2(3x-1) > log2(2-7x), we can start by applying the property of logarithms that states loga(x) > loga(y) if and only if x > y.

Therefore, we have:

3x - 1 > 2 - 7x

Now, let's solve for x:

3x + 7x > 2 + 1

10x > 3

x > 3/10

Therefore, the solution to the inequality log2(3x-1) > log2(2-7x) is x > 3/10.